morthifer
25-10-2007, 20:54
3x^3-3x^2+4x-4=0
(4-x)/(x-5)=(1)/(x-1)
(x-3)/(x-5)=2+(5-x)/(x-7)
potrafilby ktos to rozwiazac ? (:
^x - potega
/ - kreska ulamkowa
(4-x)/(x-5)=(1)/(x-1)
(x-3)/(x-5)=2+(5-x)/(x-7)
potrafilby ktos to rozwiazac ? (:
^x - potega
/ - kreska ulamkowa